What is the probability that a randomly selected patient is admitted for coronary care, oncology or both?PLEASE HELP
Hospital records show that 20% of all patients are admitted for heart disease, 24% are admitted for cancer (oncology) treatment, and 4% receive both coronary and oncology care. What is the probability that a randomly selected patient is admitted for coronary care, oncology or both?
Answer by Skeptic
The probability will be between .24 and 1.00. It will be .24 if every coronary eye car patient is also an oncology patient. It will be 1.00 if all patients who are not in for cancer treatment are treated for coronary care. It is unlikely that these events are independent so you cannot use the assumption of equal proportions.
Answer by Dave
Skeptic is correct, but let's make that radical assumption that the illnesses are independent of each other. (An absurd assumption.)
It looks like 4 out of 20 patients receive both treatments which means that 1/5 of the patients have both. If you can extend this to the general population, then you know that 1/5 or 20% of patients are admitted for coronary care.
Draw your Venn Diagram. 24% - 4% = 20% have Cancer but not both
4% have both
We project that 20% have coronary - 4% = 16 % have Coronary, but not both
Answer = 20% + 4% + 16% = 40% have oncology, both, or coronary. So the probability is .40.
Now tell your teacher that the answer is between .24 and 1.00.
Orignal From: What is the probability that a randomly selected patient is admitted for coronary care, oncology or both?
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